Question

The frequency associated with the photon of radiation having a wavelength of $6000\stackrel{o}{A}$ is:

• A. $5\times {10}^{14}Hz$
• B. $5\times {10}^{10}Hz$
• C. $2\times {10}^{14}Hz$
• D. $5\times {10}^{15}Hz$

Answer 1

Answer: (A)

$5\times {10}^{14}Hz$

In the formula; $\nu =\frac{c}{\lambda }$, c = velocity of light = $3\times {10}^8$m/s
$\lambda =6000\stackrel{o}{A}=6000\times {10}^{-10}m=6\times {10}^{-7}$ ($1\stackrel{o}{A}=1\times {10}^{-10}m$)
Therefore, $\nu =\frac{3\times {10}^8}{6\times {10}^{-7}}=5\times {10}^{14}Hz$