Calculate the heat capacity of a copper vessel of mass $150 g$ if the specific heat capacity of copper is $410 J k g^{- 1} K^{- 1}$ :

30 J K^{- 1}

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122 J K^{- 1}

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61 J K^{- 1}

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91 J K^{- 1}

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Solution

The correct option is B $61 J K^{- 1}$
Heat capacity is specific heat capacity times mass
$= 410 \times 0.15 = 61.5 J K^{- 1}$

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Similar questions

Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 $J K g^{- 1} K^{- 1}$ . How much heat energy will be required to increase the temperature of the vessel from $25^{0} C$ to $35^{0} C$ ?

(a) Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 J $k g^{- 1} K^{- 1}$ .

(b) How much heat energy will be required to increase the temperature of the vessel in part(a) from 25 $^{\circ} C t o 35^{\circ} C$ ?

Q. A copper vessel has mass

150 g

and the specific heat capacity of copper is

410 J k g^{- 1} K^{- 1}

. How much heat energy will be required to increase the temperature of the vessel in from

25^{o} C

35^{o} C

Calculate the heat capacity and water equivalent of 0.035 kg of copper . Specific heat capacity of copper is 389 JKg^-1k^-1given 1kcal=4185 J.

250 g

of water at

30^{o} C

is contained in a copper vessel of mass

50 g

. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to

5^{o} C

. Given : specific latent heat of fusion of ice

= 336 \times 10^{3} J k g^{- 1}

, specific heat capacity of copper

= 400 J k g^{- 1} K^{- 1}

, specific heat capacity of water

= 4200 J k g^{- 1} K^{- 1}

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Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410Jkg−1K−1 :

The correct option is B 61JK−1Heat capacity is specific heat capacity times mass=410×0.15=61.5JK−1

Calculate the heat capacity of a copper vessel of mass $150 g$ if the specific heat capacity of copper is $410 J k g^{- 1} K^{- 1}$ :

The correct option is B $61 J K^{- 1}$
Heat capacity is specific heat capacity times mass
$= 410 \times 0.15 = 61.5 J K^{- 1}$