Question

Calculate the minimum pressure exerted by a block of weight 50 N of dimensions 10 cm * 5 cm * 2 cmon the ground

Answer 1

Minimum pressure will be for the face where the surface area is maximum, for this block the maximum surface are of the block will be for the face 10 cm by 5 cm and the surface area will be
$A=10\times 5{\text{cm}}^2=0.1\times 0.05{\text{m}}^2=0.005{\text{m}}^2$
Hence the minimum pressure is
$P=\frac{50}{0.005}=10000{\text{Nm}}^{-2}$