Question

Calculate the moles of $BeC{l}_2.4H_{2}O$ in a 1.52 g sample.

• A. 0.01 mol
• B. 0.1 mol
• C. 0.02 mol
• D. 0.02 mol

Answer 1

The correct option is A 0.01 mol

The molar mass of $BeC{l}_2.4H_{2}O$
$=(9+35.5\times 2+8\times 1+16\times 4)g/mol$
= 152 g/mol

Therefore,
$\text{1.52 g of}BeC{l}_2.4H_{2}O=\frac{1.52}{152}\text{mol of}BeC{l}_2.4H_{2}O$

$=\text{0.01 moles of}BeC{l}_2.4H_{2}O$