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Assigning Oxidation Numbers

Calculate the...

Question

Calculate the n-factor of $S_{2} O_{3}$ for the following change.
$2 N a_{2} S_{2} O_{3} \to N a_{2} S_{4} O_{6}$

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0.5

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Solution

The correct option is D 1
For the valency factor
$2 N a_{2} S_{2} O_{3} \to N a_{2} S_{4} O_{6}$
O.S. of S in reactant side
$\Rightarrow 2 + 2 x + 3 \times (- 2) = 0$
$\Rightarrow x = + 2$

O.S. of S in product side
$\Rightarrow 2 + 4 x + 6 \times (- 2) = 0$
$\Rightarrow x = + 2.5$
$valency factor = number of S atom \times | O . S ._{P r o d u c t} - O . S ._{R e a c t a n t} |$
$valency factor = 2 \times | + 2.5 - 2 |$
$valency factor = 1$
n-factor of $N a_{2} S_{2} O_{3} = number of sulphur atom \times | O . S ._{P r o d u c t} - O . S ._{R e a c t a n t} | = 2 \times 0.5 = 1$

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