Question

calculate the no. of chlorine atoms present in 344 gms of chlorine gas.

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{Number}\mathrm{of}\mathrm{moles}\mathrm{of}{\mathrm{Cl}}_2\mathrm{gas}=\frac{\mathrm{Mass}}{\mathrm{Molar}\mathrm{mass}}=\frac{344}{70}=4.91\mathrm{mol} \\ 1\mathrm{mol}\mathrm{of}{\mathrm{Cl}}_2\mathrm{contains}6.022\times {10}^{23}\mathrm{atoms} \\ \mathrm{So},4.91\mathrm{mol}\mathrm{of}{\mathrm{Cl}}_2\mathrm{contains}=4.91\times 6.022\times {10}^{23}=2.959\times {10}^{22}\mathrm{atoms} \end{gathered}$$