Question

Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from ${35}^{\circ }C$ to ${55}^{\circ }C$. Molar heat capacity of Al is $24Jmo{l}^{-1}{K}^{-1}$

Answer 1

From the expression of heat (q),
q = m. c. $\Delta T$ Where,
c = molar heat capacity m
= mass of substance
$\Delta T$ = change in temperature
Substituting the values in the expression of q:
$q=\left(\frac{60}{27}mol\right)\left(24Jmo{l}^{-1}{K}^{-1}\right)\left(20K\right)q=1066.7Jq=1.07kJ$