Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35 C to 55 C. Molar heat capacity of $A l$ is 24 J mol $K^{- 1}$ :

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Solution

Amount of heat $(Q) =$ $n C Δ T$

Given, number of moles of $A l = \frac{609}{27} = 2.22$ moles

Specific heat $= C = 24 J m o l K$ $^{- 1}$

$Δ T$ $= 55^{o} - 35^{o} = 20^{o} C$

$Q = (2.22) (24) (20) = 1066.67$

Number of kilojoules of heat required $= 1.066$ kJ

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Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from $35^{\circ} C$ to $55^{\circ} C$ . Molar heat capacity of Al is $24 J m o l^{- 1} K^{- 1}$

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Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35 C to 55 C. Molar heat capacity of Al is 24 J mol K−1 :

Amount of heat (Q)= nCΔTGiven, number of moles of Al=60927=2.22 molesSpecific heat =C=24 Jmol K −1ΔT =55o−35o=20oCQ=(2.22)(24)(20)=1066.67Number of kilojoules of heat required =1.066 kJ

Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35 C to 55 C. Molar heat capacity of $A l$ is 24 J mol $K^{- 1}$ :

Amount of heat $(Q) =$ $n C Δ T$

Given, number of moles of $A l = \frac{609}{27} = 2.22$ moles

Specific heat $= C = 24 J m o l K$ $^{- 1}$

$Δ T$ $= 55^{o} - 35^{o} = 20^{o} C$

$Q = (2.22) (24) (20) = 1066.67$

Number of kilojoules of heat required $= 1.066$ kJ