calculate the number of molecules of glucose present in its 90 gm ( molecules mass of glucose is 180u ) (6.02×1023 mol -1)

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Solution

Hi,

1 mole of glucose = 6.02 X 10²³ molecules = 180 g of glucose

90 g of glucose = $\frac{6.02 \times 10^{23}}{2} = 3.01 \times 10^{23} molecules$

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