Question

Calculate the number of moles of $H_{2}S{O}_4$ present in $10ml$ of $N/2H_{2}S{O}_4$ solution.

Answer 1

Number of replacable $H^{+}$ ions in $H_{2}S{O}_4\left(n\right)=2$

Normality= $n\times Molarity$

$\therefore$ Molarity=$\frac{1/2}{2}M=0.25$ $M$

Molarity=$\frac{Molesof{H}_{2}S{O}_4}{VolumesinLitres}$

$\therefore$ Moles of $H_{2}S{O}_4=0.25\times 0.010$

=$2.5\times {10}^{-3}$ $M$

$\therefore$ Number of moles of $H_{2}S{O}_4$ present are $2.5\times {10}^{-3}$ $M$.