Question

Calculate the number of moles of $KMn{O}_4$ that will be neded to react completely with one mole of ferrous oxalate $Fe\left(C_2{O}_4\right)$ in acidic solution is:

• A. $2/5$
• B. $3/5$
• C. $6/5$
• D. $2$

Answer 1

The correct option is B $3/5$

$3Mn{O}_4^{-}+5(F{e}^{2+}+C_2{O}_4^{2-})+24H^{+}\to 3M{n}^{2+}+5F{e}^{3+}+10C{O}_2+12H_{2}O$

Thus $5\text{M}$ of $Fe{C}_2{O}_4$ is oxidised by $3\text{M}$ of $KMn{O}_4$ then $1\text{M}$ of $Fe{C}_2{O}_4$ is oxidised by $3/5$ mole of $KMn{O}_4.$