Calculate the percentage of phosphorus in the fertilizer, superphosphate $C a (H_{2} P O_{4})_{2}$ . [H = 1, O = 16, P = 31, C = 40]

32.5 %

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21.0 %

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26.5 %

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31.5 %

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Solution

The correct option is C
26.5 %

Molecular weight of $C a (H_{2} P O_{4})_{2}$

= $40 + 2 (2 \times 1 + 31 + 4 \times 16)$

= $40 + 2 \times 97$

=40+194

=234 g.

Amount of phosphorous in $C a (H_{2} P O_{4})_{2}$

= 2 $\times$ 31 = 62 g.

Percentage of phosphorous = $\frac{62 \times 100}{234}$ = 26.5%

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Similar questions

Calculate the percentage of phosphorus in the fertilizer, superphosphate $C a (H_{2} P O_{4})_{2}$ .(Correct to 1 decimal point). [H = 1, O = 16, P = 31, C = 40]

Calculate the percentage of phosphorus in the fertilizer superphosphate, Ca(H₂PO₄)₂ (correct to 1 decimal place.) [Ca = 40, H = 1, P = 31, O = 16]

Q. The percentage of phosphorus in the fertilizer superhosphate

C a (H_{2} P O_{4})_{2}

is :

[

H = 1; O = 16; P = 31; C a = 40

]

Find the percentage of
(a) oxygen in magnesium nitrate crystals $[M g (N O_{3})_{2} 6 H_{2} O]$ .
(b) boron in $N a_{2} B_{4} O_{7} . 10 H_{2} O . [H = 1, B = 11, O = 16, N a = 23] .$
(c) phosphorus in the fertilizer superphosphate $C a (H_{2} P O_{4})_{2}$

(i) Calculate the percentage of phosphorus in the fertilizer superphosphate Ca(H₂PO₄)₂.
(H = 1; O = 16; P = 31; Ca = 40)
(ii) Write out and balance the following equation correctly:
Ca₃(PO₄)₂ + H₂SO₄ $\overset{}{\to}$ Ca(H₂PO₄)₂ + CaSO₄
(iii) Copy and complete the following sentence:
Superphosphate is an example of a compound called___________(acid salt / basic salt / normal salt).

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Calculate the percentage of phosphorus in the fertilizer, superphosphate Ca(H2PO4)2. [H = 1, O = 16, P = 31, C = 40]

The correct option is C 26.5 % Molecular weight of Ca(H2PO4)2 = 40+2(2×1+31+4×16) = 40+2×97 =40+194 =234 g. Amount of phosphorous in Ca(H2PO4)2​ = 2 × 31 = 62 g. Percentage of phosphorous = 62×100234 = 26.5%

Calculate the percentage of phosphorus in the fertilizer, superphosphate $C a (H_{2} P O_{4})_{2}$ . [H = 1, O = 16, P = 31, C = 40]