Calculate the percentage of sulphur in $H_{2} {S O}_{4}$ .

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Solution

Molecular weight of $H_{2} S O_{4} = (1 \times 2 + 32 \times 1 + 16 \times 4)$
$= 98$

The molecular weight of $S = 32$

$%$ of sulfer in $H_{2} S O_{4} = \frac{32}{98} \times 100$

$= 32.65 %$

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