Calculate the pressure at a depth of $100 m$ below the surface of the sea. The density of sea water is $1024 \frac{k g}{m^{3}}$ .

$1024000 P a$

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$102400 P a$

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$10240 P a$

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None of these

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Solution

The correct option is A
$1024000 P a$

The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by $d g h$ .
The given values are: $d = 1024 \frac{k g}{m^{3}}$ , $h = 100 m a n d g = 10 \frac{m}{s^{2}}$ .
Thus, $p r e s s u r e = d g h = 1024$ $\times 100$ $\times 10 = 1024000 P a$ .

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Calculate the pressure at a depth of 100m below the surface of the sea. The density of sea water is 1024kgm3.

The correct option is A 1024000Pa The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by dgh. The given values are: d=1024kgm3,h=100m and g=10ms2. Thus, pressure=dgh=1024 ×100 ×10=1024000Pa.

Calculate the pressure at a depth of $100 m$ below the surface of the sea. The density of sea water is $1024 \frac{k g}{m^{3}}$ .