Calculate the pressure exerted by the waters of the Bay of Bengal near Puducherry, at a depth of 11.0 km. (consider density = $1025 k g / m^{3}$ )

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Solution

$P r e s s u r e = ρ g h$ .
Where $h = d e p t h = 11 k m = 11000 m$
$ρ = d e n s i t y = 1025 k g / m^{3}$
$g = 9.8 m / s^{2}$

$p r e s s u r e = 11000 * 1025 * 9.8$
$= 1.1 * 10^{8} N / m^{2}$

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