Calculate the pressure exerted (in Pa) by $0.8 m$ vertical length of alcohol of density $0.8 g$ ${c m}^{- 3}$ . (Acceleration due to gravity $(g) = 10 m$ $s^{- 2}$ )

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Solution

Hydrostatic Pressure = $ϱ g h$ = 800kg/ $m^{3}$ $\times 10 {m s}^{- 2} \times 0.8 m$
Hydrostatic Pressure = 6400 $P_{a}$

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Calculate the pressure exerted (in Pa) by 0.8m vertical length of alcohol of density 0.8g cm−3. (Acceleration due to gravity (g)=10m s−2)

Hydrostatic Pressure = ϱgh = 800kg/m3×10ms−2×0.8mHydrostatic Pressure = 6400 Pa

Calculate the pressure exerted (in Pa) by $0.8 m$ vertical length of alcohol of density $0.8 g$ ${c m}^{- 3}$ . (Acceleration due to gravity $(g) = 10 m$ $s^{- 2}$ )

Hydrostatic Pressure = $ϱ g h$ = 800kg/ $m^{3}$ $\times 10 {m s}^{- 2} \times 0.8 m$
Hydrostatic Pressure = 6400 $P_{a}$