Question

Calculate the temperature at which the root mean square speed of ${SO}_2$ molecules is the same as that of oxygen at ${27}^{o}C$.

• A. 400
• B. 500
• C. 600
• D. 700

Answer 1

The correct option is C 600

$V_{rms}=\sqrt{\frac{3RT}{M}}$

${27}^{\circ }C=300K$

M of $S{O}_2=64g$

M of $S{O}_2=16\left(2\right)=32g$

$\sqrt{\frac{3RT}{64}}$ $=\sqrt{\frac{3R\left)\right(300)}{32}}$

$\Rightarrow \sqrt{\frac{T}{64}}$ $=\sqrt{\frac{300}{32}}$

$\Rightarrow T=600K$