Calculate the value of E-MnO4-MnO2- MnO4-8H-5e- Mn2-4H2O- E-1-51V MnO2-4H-2e- Mn2-2H2O- E-1-23V

The correct option is A 1.70 V On subtracting eqn. (ii) from (i) we get MnO_4^ +4H^++3e^ → MnO_2+2H_2O ∴ E_3= 1.51× 5+2× 1.23/3 ∴ E_3=1.70 ...

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Question

Calculate the value of $E_{M n O_{4}^{-} | M n O_{2}}^{\circ}$ .

$M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O$ ; $E^{\circ} = 1.51 V$
$M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O$ ; $E^{\circ} = 1.23 V$

1.70 V

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0.91 V

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1.37 V

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0.548 V

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M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O; E^{O} = 1.51 V; Δ G_{1}^{0} = - 5 \times 1.51 \times F

M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O; E^{O} = 1.23 V; Δ G_{2}^{0} = - 5 \times 1.23 \times F

E_{M n O_{4}^{-} | M n O_{2}}^{\circ}

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O; E^{o} = X_{1} V

M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O; E^{o} = X_{2} V

E^{o}

M n O_{4}^{-} + 4 H^{+} + 3 e^{-} \to M n O_{2} + 2 H_{2} O

M n O_{4}^{-} / M n O_{2}

M n O_{4}^{-} / M n^{2 +} = 1.51 V

M n O_{2} / M n^{2 +} = 1.23 V

E^{o}

M n^{2 +} + 2 H_{2} O \to M n O_{2} + 4 H^{+} + 2 e^{-}

E^{o} = - 1.23 V

M n O_{4}^{-} + 4 H^{+} + 3 e^{-} \to M n O_{2} + 2 H_{2} O

E^{o} = + 1.70 V

5 {F e}^{2 +} + M n O_{4}^{-} + 8 H^{+} ⇌ {M n}^{2 +} + 5 {F e}^{3 +} + 4 H_{2} O

{F e}^{3 +} + e^{-} ⟶ {F e}^{2 +}, {E_{1}}^{o}

M n O_{4}^{-} + 8 H^{+} + 5 e^{-} ⟶ {M n}^{2 +} + 4 H_{2} O, {E_{2}}^{o}

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