Calculate the volume occupied by 4 mole of an ideal gas at 2-5- 105Nm-2 pressure and 300 K temperature-

Using ideal gas equation : V = nRTP Given : #160; n = 4 #160; R = 8.314 Nm K^ 1mol^ 1 T = 300, P = 2.5× 10^5 Nm^ 2 V = 4× 8.314× ...

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Standard X

Chemistry

Gay Lussac's Law

Calculate the...

Question

Calculate the volume occupied by $4$ mole of an ideal gas at $2.5 \times 10^{5} N m^{- 2}$ pressure and $300 K$ temperature.

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Solution

Using ideal gas equation :

$V = \frac{n R T}{P}$

Given :

$n = 4$

$R = 8.314 N m K^{- 1} m o l^{- 1}$

$T = 300, P = 2.5 \times 10^{5} N m^{- 2}$

$V$ = $\frac{4 \times 8.314 \times 300}{2.5 \times 10^{5}}$

= $39.9 d m^{3}$

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Calculate the volume occupied by 4 mole of an ideal gas at 2.5×105Nm−2 pressure and 300 K temperature.

Using ideal gas equation :V=nRTPGiven : n=4 R=8.314 Nm K−1mol−1T=300,P=2.5×105Nm−2V =4×8.314×3002.5×105 =39.9 dm3

Calculate the volume occupied by $4$ mole of an ideal gas at $2.5 \times 10^{5} N m^{- 2}$ pressure and $300 K$ temperature.

Using ideal gas equation :

$V = \frac{n R T}{P}$

Given :

$n = 4$

$R = 8.314 N m K^{- 1} m o l^{- 1}$

$T = 300, P = 2.5 \times 10^{5} N m^{- 2}$

$V$ = $\frac{4 \times 8.314 \times 300}{2.5 \times 10^{5}}$

= $39.9 d m^{3}$