Question

Calculate the volume of air needed for the combustion of 1 kg of carbon.

Answer 1

$C_{\left(s\right)}+O_{2\left(g\right)}=C{O}_{2\left(g\right)}+△$

$12g32g$

$\because 12g$ of carbon requires $O_2=32g,$

$\therefore 100g$ of carbon requires $O_2=\frac{8000}{3}g$

As, $density=\frac{Mass}{Volume}$

$\because Density$ of $O_2$ at NTP $=1.428gm/L$

$Volume=\frac{Mass}{Density}=\frac{\frac{8000}{3}}{1.428}=1.86\times {10}^{3}L$