Calculate the wave number of the second line in Balmer series

Open in App

Solution

Figure wave number of first line of balmer arrangement for lithium positive 2 The wavenumber (w) is specifically relative to the recurrence. Doubly ionized lithium (Li++ particle) is a hydrogen-like molecule in that it has only one electron, yet the nuclear number (Z) is 3. The summed up Rydberg recipe for hydrogen-like particles of nuclear number Z then moves toward becoming: f = Z²cR(1/L² - 1/U²). So if Z = 3, f (and furthermore w) are increased by a component of Z² or 9 for the Li++ particle. In the event that w for customary hydrogen is 15200 waves for each cm. at that point w for doubly ionized Li is 9 times that, or 136,800 waves for each cm

Suggest Corrections

Similar questions

Q. The wave number of first line in Balmer series of hydrogen is

15200 {c m}^{- 1}

. What is the wave number of first line in Balmer series of

{B e}^{3 +}

_{If the wavelength of the first line in the Balmer series is 656nm. Calculate the wavelength of the second line and the limiting line in Balmer series.}

Q. The wave number of the first line in the Balmer series of hydrogen atom is

15200 c m^{- 1}

. What is the wave number of the first line in the Balmer series of

B e^{3 +}

Q. If the wave number of the first line in the Balmer series of hydrogen atom is

15000 c m^{- 1}

, the wave number of the first line of the Balmer series of

L i^{2 +}

Q. The wave number of the first line of Balmer series of hydrogen is

15200 {c m}^{- 1}

. The wave number of the first line of Balmer series for

L i^{2 +}

ion is:

Join BYJU'S Learning Program