Calculate the wavelength associated with an electron moving with a velocity of $10^{10} c m / s .$

0.072 \circ A

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0.829 \circ A

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0.667 \circ A

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1.009 \circ A

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Solution

The correct option is A $0.072 \circ A$
Given :
$Planck's constant (h) = 6.63 \times 10^{- 27} e r g s Velocity of electron (v) = 10^{10} c m / s$
We know that:
$Mass of electron (m_{e}) = 9.1 \times 10^{- 28} g$
$de Broglie wavelength (λ) = \frac{h}{m v} = \frac{6.63 \times 10^{- 27}}{9.1 \times 10^{- 28} \times 10^{10}} = 7.28 \times 10^{- 10} c m = 0.072 \circ A$

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De Broglie's Hypothesis

Standard XIII Chemistry

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Calculate the wavelength associated with an electron moving with a velocity of 1010cm/s.

The correct option is A 0.072∘AGiven : Planck's constant(h)=6.63×10−27ergsVelocity of electron (v)=1010cm/s We know that: Mass of electron(me)=9.1×10−28g de Broglie wavelength(λ)=hmv=6.63×10−279.1×10−28×1010=7.28×10−10cm=0.072∘A

Calculate the wavelength associated with an electron moving with a velocity of $10^{10} c m / s .$