Calculate the wavelength of an electron moving with a velocity of 2.05 × 107ms^–1.

Open in App

Solution

According to de Broglie’s equation,
λ=hmv
Where, λ = wavelength of moving particle
m = mass of the particle
v = velocity of the particle
h = Planck’s constant
Substituting the values in the expression of λ:
λ=6.626×10⁻³⁴Js
(9.10939×10⁻³¹kg)(2.05×107)ms⁻¹
Hence, the wavelength of the electron moving with a velocity of 2.05 × 107ms^–1 is 3.548 × 10^–11 m.

Suggest Corrections

161

Similar questions

Q. Calculate the wavelength of the electron if it moving with a velocity of

2.05 \times 10^{7} m s^{- 1}

Q. The wavelength of an electron moving with velocity of

10^{7} m s^{- 1}

is:

Q. What is the wavelength associated with an electron moving with a velocity of

4 \times 10^{7} m s^{- 1}

If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 × $10^{7} m s^{- 1}$ , calculate the energy with which it is bound to the nucleus.

Q. If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of

1.5 \times 10^{7} m s^{- 1}

, calculate the energy with which it is bound to the nucleus.

Join BYJU'S Learning Program

Explore more

De Broglie's Hypothesis

Standard XII Chemistry

Join BYJU'S Learning Program

Calculate the wavelength of an electron moving with a velocity of 2.05 × 107ms–1.

Calculate the wavelength of an electron moving with a velocity of 2.05 × 107ms^–1.