Calculate the wavelength of an electron moving with a velocity of $2.05 \times 10^{7} m s^{- 1}$ .

Open in App

Solution

The wavelength of an electron is obtained from de-Broglie equation.
$λ = \frac{h}{m v}$
$= \frac{6.626 \times 10^{- 34} J s}{9.11 \times 10^{- 31} k g \times 2.05 \times 10^{7} m / s}$
$= 3.55 \times 10^{- 11} m$

Suggest Corrections

Similar questions

Q. Calculate the wavelength of the electron if it moving with a velocity of

2.05 \times 10^{7} m s^{- 1}

Q. The wavelength of an electron moving with velocity of

10^{7} m s^{- 1}

is:

Q. What is the wavelength associated with an electron moving with a velocity of

4 \times 10^{7} m s^{- 1}

If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 × $10^{7} m s^{- 1}$ , calculate the energy with which it is bound to the nucleus.

Q. If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of

1.5 \times 10^{7} m s^{- 1}

, calculate the energy with which it is bound to the nucleus.

Join BYJU'S Learning Program

Calculate the wavelength of an electron moving with a velocity of 2.05×107ms−1.

The wavelength of an electron is obtained from de-Broglie equation.λ=hmv =6.626×10−34Js9.11×10−31kg×2.05×107m/s =3.55×10−11m

Calculate the wavelength of an electron moving with a velocity of $2.05 \times 10^{7} m s^{- 1}$ .

The wavelength of an electron is obtained from de-Broglie equation.
$λ = \frac{h}{m v}$
$= \frac{6.626 \times 10^{- 34} J s}{9.11 \times 10^{- 31} k g \times 2.05 \times 10^{7} m / s}$
$= 3.55 \times 10^{- 11} m$