wiz-icon
MyQuestionIcon
MyQuestionIcon
11
You visited us 11 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the work done when one mole of gas is allowed to expand freely in vacuum.

A
20 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
10 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0 J
Gas expands in vacuum, so it is a case of free expansion i.e., Pext=0 and thus, it is an irreversible process.
Therefore, W=Pext(V2V1)=0
In free expansion, the gas is expanding in vaccuum and the molecules move freely i.e the gas expands against no force.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon