Calculate f G 0 in kJ mol -1 for NH 4 Cl - s at 310 K-Given - f H 0 NH 4 Cl - s -314-5 kJmol -1 - r C p -0S N 2 g 0-192 JK -1 mol -1 - S H 2 g 0-130-5 JK -1 mol -1S Cl 2 O g -233 JK -1 mol -1 - S NH 4 Cl s 0-99-5 JK -1 mol -1All given data are at 300 K- A- -198-56B- -426-7C- -202-3D- None of these

The correct option is A 198.56Given : _fH^o (NH_4Cl, s) = 314.5 kJ/mol; _r C_p = 0 S^o _N_2 = 192 JK^ 1 mol^ 1; S^o _H_2 = 130.5 JK^ 1 mol^ 1; ...

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Byju's Answer

Standard XII

Chemistry

Heat of Formation

Calculate f G...

Question

Calculate $△_{f} G^{o}$ in $k J m o l^{- 1}$ for $(N H_{4} C l, s)$ at 310 K.
Given : $△_{f} H^{o} (N H_{4} C l, s) = - 314.5 k J m o l^{- 1}; △_{r} C_{p} = 0$

$S_{N_{2} (g)}^{o} = 192 J K^{- 1} m o l^{- 1}; S_{H_{2} (g)}^{o} = 130.5 J K^{- 1} m o l^{- 1};$
$S_{C l_{2}}^{o} (g) = 233 J K^{- 1} m o l^{- 1}; S_{N H_{4} C l (s)}^{o} = 99.5 J K^{- 1} m o l^{- 1}$

All given data are at 300 K.

- 198.56

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- 426.7

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- 202.3

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None of these

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Solution

The correct option is A $- 198.56$
Given : $△_{f} H^{o} (N H_{4} C l, s) = - 314.5 k J / m o l; △_{r} C_{p} = 0$

$S_{N_{2}}^{o} = 192 J K^{- 1} m o l^{- 1}; S_{H_{2}}^{o} = 130.5 J K^{- 1} m o l^{- 1};$

$S_{C l_{2}}^{o} = 233 J K^{- 1} m o l^{- 1}; S_{N H_{4} C l}^{o} = 99.5 J K^{- 1} m o l^{- 1}$

$△_{f} S^{o} (N H_{4} C l, s) a t 300 K$

$= S_{N H_{4} C l (s)} - [\frac{1}{2} S_{N_{2}} (g) + 2 S_{H_{2}} (g) + \frac{1}{2} S_{C l_{2}} (g)]$
$= - 374 J K^{- 1} m o l^{- 1}$

$△_{f} C_{P} = 0$

$△_{f} S_{310}^{o} = △_{f} S_{300}^{o}$
$= - 374 J K^{- 1} m o l^{- 1}$

$△_{f} H_{310}^{o} = △_{f} H_{300}^{o} = - 314.5$
$△ G_{310}^{o} = △_{f} H^{o} - 310 △ S^{o}$
$= - 314.5 - \frac{310 (- 374)}{1000} = - 198.56 k J / m o l .$

hence, $△_{f} G^{o} = - 198.56 k J m o l^{- 1}$

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Similar questions

Q. Calculate

Δ_{f} G^{\circ}

for

(N H_{4} C l, (s))

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Given:

Δ_{f} H^{\circ} (N H_{4} C l, s) = - 314.5 k J / m o l : Δ_{r} C_{p} = 0

S_{N_{2} (g)}^{\circ} = 192 J K^{- 1} m o l^{- 1}; S_{H_{2} (g)}^{\circ} = 130.5 J K^{- 1} m o l^{- 1} S_{C l_{2} (g)}^{\circ} = 233 J K^{- 1} m o l^{- 1}; S_{N H_{4} C l (s)}^{\circ} = 99.5 J K^{- 1} m o l^{- 1}

All given data at

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Q. Calculate

Δ_{f} G^{\circ}

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Given:

Δ_{f} H^{\circ} (N H_{4} C l, s) = - 314.5 k J / m o l : Δ_{r} C_{p} = 0

S_{N_{2} (g)}^{\circ} = 192 J K^{- 1} m o l^{- 1}; S_{H_{2} (g)}^{\circ} = 130.5 J K^{- 1} m o l^{- 1} S_{C l_{2} (g)}^{\circ} = 233 J K^{- 1} m o l^{- 1}; S_{N H_{4} C l (s)} 99.5 J K^{- 1} m o l^{- 1}

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Q. The

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Given:

Δ_{f} H^{\circ} (N H_{4} C l, s) = - 314.5 {kJ mol}^{- 1}; Δ_{r} C_{P} = 0 S_{N_{2} (g)}^{\circ} = 192 {J K}^{- 1} {mol}^{- 1}; S_{H_{2} (g)}^{\circ} = 130.5 {J K}^{- 1} {mol}^{- 1} S_{C l_{2} (g)}^{\circ} = 223 {J K}^{- 1} {mol}^{- 1}; S_{N H_{4} C l (s)}^{\circ} = 99.5 {J K}^{- 1} {mol}^{- 1}

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Q. Calculate the entropy change for the following reaction,

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S_{H_{2}}^{⊖} = 131 J K^{- 1} m o l^{- 1}

S_{C l_{2}}^{⊖} = 223 J K^{- 1} m o l^{- 1}

and

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Heat of Formation

Standard XII Chemistry

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Calculate △fGoin kJmol−1 for (NH4Cl,s) at 310 K. Given : △fHo(NH4Cl,s)=−314.5 kJmol−1; △rCp=0 SoN2(g)=192 JK−1 mol−1; SoH2(g)=130.5 JK−1 mol−1; SoCl2(g)=233 JK−1 mol−1; SoNH4Cl(s)=99.5 JK−1 mol−1 All given data are at 300 K.