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Question

Case study (2)

In the circuit shown in figure, four capacitors are connected to a battery.

(iii)The potential difference across the 6 μF capacitor is


A
6 V
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B
4 V
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C
5 V
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D
7 V
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Solution

The correct option is A 6 V
We can redraw the given circuit as follows,


The net charge through the battery is,

Qnet=CeqV=6×10=60 μC [Ceq=6 μF]

Now, charge through 6 μF capacitor is,

q6 μF=610×60 μC=36 μC

Now, potential difference across the 6 μF capacitor is,

V6 μF=QC=366=6 V

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (A) is the correct answer.

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