wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Case study (2)

In the circuit shown in figure, four capacitors are connected to a battery.

(iii)The potential difference across the 6 μF capacitor is


A
6 V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
7 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 6 V
We can redraw the given circuit as follows,


The net charge through the battery is,

Qnet=CeqV=6×10=60 μC [Ceq=6 μF]

Now, charge through 6 μF capacitor is,

q6 μF=610×60 μC=36 μC

Now, potential difference across the 6 μF capacitor is,

V6 μF=QC=366=6 V

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (A) is the correct answer.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon