$C H_{3} - C H_{2} - C H_{2} - B r \to C H_{3} - C H_{2} - C H_{2} - C H_{3}$

The most effective reagent for the above transformation is:

Z n / H^{+}

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C u I

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C H_{3} M g C l

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(C H_{3})_{2} C u L i

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Solution

The correct option is D $(C H_{3})_{2} C u L i$
$C H_{3} - C H_{2} - C H_{2} - B r (C H_{3})_{2} C u L i - ------ \to C H_{3} - C H_{2} - C H_{2} - C H_{3}$
This reaction goes through $S_{N} 2$ pathway. Grignard reagent gives poor yield.

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Similar questions

C H_{3} - C H_{2} - C H_{2} - B r \to C H_{3} - C H_{2} - C H_{2} - C H_{3}

C H_{3} - C H = C H - C H_{2} - O H | C H - C H_{3} ⟶ C H_{3} - C H = C H - C H_{2} - C O O H

C H_{2} = C H_{2} + H_{2} N i ⟶ C H_{3} - C H_{3}

S_{N} 2

K I

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

(I) (I I)

C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

(I) (I I)

C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

(I) (I I)

C H_{3} - H | C | O H - C H_{2} - C H_{2} - C H_{2} - B r | C | B r - C H_{3}

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