$C H_{3} - C | C H_{3} H - C H_{2} - C H_{3} C l_{2} - - \to h v$
Number of chiral centers generated during monochlorination in the above reaction.

1

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2

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3

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4

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Solution

The correct option is B $1$
$C H_{3} - C H - C H_{2} C H_{3} \frac{C l_{2}}{H_{2}}$
The monochlorinated products are
$C H_{3} - C H - C H_{2} C l$ .
Only one of the monochlorinated product has one chiral carbon.

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