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Introduction to E2 Mechanism

CH3CH2MgCl wh...

Question

$C H_{3} C H_{2} M g C l$ when reacts with heavy water, the product obtained is:

C D_{3} - C H_{2} D

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C H_{3} C H_{2} - O D

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C D_{3} - C D_{3}

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C H_{3} C H_{2} D

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Solution

The correct option is D $C H_{3} C H_{2} D$
The reaction of ethylmagnesium chloride with heavy water forms mono deuterated ethane. $C H_{3} C H_{2} M g C l + D O D \to C H_{3} C H_{2} D + M g C l O D$ .

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Similar questions

+ I

- C H_{3}, - C H_{2} R, - C D_{3}

R

C H_{3} - C H_{3}

C D_{3} - C D_{3}

C H_{3} - C H_{3} | C | C H_{3} - C H_{3}

f = {c d}^{3}

f = 450

d = 10

c

	Column I		Column II
A	$C H_{3} - C H B r - C D_{3}$ /on treatement with alc.KOH gives $C H_{2} = C H - C D_{3}$ as a major product	P	E1 reaction
B	$P h - C H B r - C H_{3}$ reacts faster than $P h - C H B r - C D_{3}$	Q	E2 reaction
C	$P h - C H_{2} - C H_{2} - F$ on treatement with $C_{2} H_{5} O D / C_{2} H_{5} O^{-}$ gives $P h - C D = C H_{2}$ as the major product	R	E1cB reaction
D	$P h - C H_{2} - C H_{2} - B r$ and $P h - C D_{2} - C H_{2} - B r$ react with same rate	S	First order reaction

+ I

- C H_{3}

- C D_{3}

- C T_{3}

- C H D_{2}

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