CH3MgBr +CH_2=CH-CHO \xrightarrow{H_3O^+} PRODUCT, IT IS 1 CH2=CH-CH(OH) CH3 2 CH2(OH) CH=CH-CH3 3 CH3CH2CH2CHO 4 NONE OF THESE

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C H_{3} - C H = C H - C H_{2} O H P C C - -- \to Product

7 C H_{3} - 6 C H_{2} - 5 C | H C H_{3} - 4 C H = 3 C H - 2 C H_{2} - 1 C H O

Which of the following compounds gives fastest reaction with HBr and why

(i) (CH3)3 COH

(ii) CH3 CH2 CH2OH

(iii) CH3 CHOH CH3

(iv) CH3 (CH3) CH CH2OH

The IUPAC name of

$C H_{3} - C H | C H_{3} - C | C H_{3} - C H | C H O - C H_{2} - C H_{2} - C H_{3}$ is?

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