Chloroethane reacts with Y to form NaCl and Z. One mole of Z reacts with two moles of HI to form water and iodoethane. Which of the following is Y?

C H_{3} C O O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2} H_{5} O C_{2} H_{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2} H_{5} O N a

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $C_{2} H_{5} O N a$
$Z + 2 H I ⟶ H_{2} O + C H_{3} C H_{2} I$

This means $Z$ is an ether with ethyl group on both sides of oxygen or it is diethyl ether.

$C H_{3} C H_{2} C l + Y ⟶ N a C l + C H_{3} C H_{2} - O - C H_{2} C H_{3}$

This means that $Y$ is an alkoxide ion or more specifically ethoxide ion, i.e., $C_{2} H_{5} O N a$ .

Because, $C H_{3} C H_{2} C l + C_{2} H_{5} O N a ⟶ N a C l + C_{2} H_{5} - O - C_{2} H_{5}$

Suggest Corrections

Similar questions

H C l

N a C l

H_{2} O

X

Y

X

N a_{2} S

N a_{2} S_{2} O_{3}

Y

Y

B r_{2}

H_{2} S O_{4}

C_{5} H_{10}

C_{5} H_{10}

Join BYJU'S Learning Program