Choose the correct answer in each of the following questions:
In a frequency distribution, the mid-value of a class is 10 and width of each class is 6. The lower limit of the class is
(a) 6
(b) 7
(c) 8
(d) 12

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Solution

NSWER:
(b) 7
Given:
Mid value of the class = 10
Width of each class = 6
Now,
Let the lower limit be x.
We know:
Upper limit = Lower limit + Class size
= x + 6
Also,
x+x+6
Mid value =

2x+6/2

= x + 3 ⇒ x + 3 = 10 ⇒ x = 7
Thus, the lower limit is 7.

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Q. In a frequency distribution, the mid-value of a class is 10 and width of each class is 6. The lower limit of the class is
(a) 6
(b) 7
(c) 8
(d) 12

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Q. In the frequency distribution the mid value of a class is 10 and the width of the class is 6 The lower limit of the class is

In a frequency distribution, the mid-value of a class is $10$ and the width of the class is $6$ . The lower limit of the class is:
A) $6$
B) $7$
C) $8$
D) $12$

Choose the correct answer in each of the following questions:
The width of each of the five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
(a) 45
(b) 25
(c) 35
(d) 40

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Choose the correct answer in each of the following questions: In a frequency distribution, the mid-value of a class is 10 and width of each class is 6. The lower limit of the class is (a) 6 (b) 7 (c) 8 (d) 12

NSWER: (b) 7 Given: Mid value of the class = 10 Width of each class = 6 Now, Let the lower limit be x. We know: Upper limit = Lower limit + Class size = x + 6 Also, x+x+6 Mid value = 2x+6/2 = x + 3 ⇒ x + 3 = 10 ⇒ x = 7 Thus, the lower limit is 7.

Choose the correct answer in each of the following questions:
In a frequency distribution, the mid-value of a class is 10 and width of each class is 6. The lower limit of the class is
(a) 6
(b) 7
(c) 8
(d) 12

NSWER:
(b) 7
Given:
Mid value of the class = 10
Width of each class = 6
Now,
Let the lower limit be x.
We know:
Upper limit = Lower limit + Class size
= x + 6
Also,
x+x+6
Mid value =

2x+6/2

= x + 3 ⇒ x + 3 = 10 ⇒ x = 7
Thus, the lower limit is 7.