$C l_{2} O_{7}$ is the anhydride of :

H O C l

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H C l O_{2}

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H C l O_{3}

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H C l O_{4}

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Solution

The correct option is D $H C l O_{4}$
$C l_{2} O_{7}$ is the anhydride of $H C l O_{4}$ .

$2 H C l O_{4} - H_{2} O ⟶ C l_{2} O_{7}$ .

Hence, option D is correct.

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