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Question

Clay found in a lake at Bhopal contains 15% by mass moisture along with CaCO3 and non volatile SiO2. This on heating loses a part of its moisture, but CaCO3 is completely converted into CaO. The partially dried sample now contains 7.3% moisture and 51.5% SiO2. What is the mass percentage of CaCO3 in the original sample of clay approximately?

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Solution

Let % of CaCO3 be x and we take 100 gm of clay then,
Mass of SiO2=85x
After heating SiO2 is 51.5% and CaO is 41.2% as moisture is 7.3%
Since the mass of SiO2 will remain same, then
51.5100 × weight of the clay after heating = 85x weight of the clay after heating = (85x)10051.5.
So, mass of the CaO
=(85x)10051.5×(41.2100) ---- (1)
Since CaCO3 is completely converted to CaO, the number of moles of CaO and CaCO3 are the same.
So mass of CaO will be x100×56 ----(2)
From equations (1) and (2),
(85x)10051.5×(41.2100)=x100×56
x=50 gm

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