Coffee costing $R s . 250$ per $k g$ was mixed with chicory costing $R s . 75$ per $k g$ in the ratio $5 : 2$ for a certain blend. If the mixture was sold at $R s . 230$ per $k g$ , find the gain or loss per cent.

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Solution

cost of coffee $= 250 p e r k g$ .
cost of chicory $= 75 p e r k g$
coffee: chicory $5 : 2$
if the weight of mixture is $1 k g .$
$\frac{5 x + 2 x}{7} = 1$
$\Rightarrow 7 x = 7$
$\Rightarrow x = 1$
$∴$ weight of coffee = $\frac{5 x}{7} = \frac{5}{7} k g$
weight of chicory = $\frac{2 x}{7} = \frac{2}{7} k g$
cost of $\frac{5}{7}$ kg coffee = $\frac{5}{7} \times 250 = \frac{1250}{7}$
cost of $\frac{2}{7}$ kg chicory = $\frac{2}{7} \times 75 = \frac{150}{7}$
total cost of $1 k g$ mixture = $\frac{1250}{7} + \frac{150}{7}$
cost price of $1 k g$ mixture = $\frac{1400}{7} = 200 R s$
selling of $1$ kg minute = $230 R s$
$S P > C P,$ so it is a case of gain.
gain $% = \frac{S P - C P}{C P} \times 100 % = \frac{230 - 200}{200} \times 100 %$
= $\frac{30}{2} = 15$ %
Hence, the mixture was sold at a gain of $15 %$ .

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Coffee costing Rs.250 per kg was mixed with chicory costing Rs.75 per kg in the ratio 5:2 for a certain blend. If the mixture was sold at Rs.230 per kg , find the gain or loss per cent.

Coffee costing $R s . 250$ per $k g$ was mixed with chicory costing $R s . 75$ per $k g$ in the ratio $5 : 2$ for a certain blend. If the mixture was sold at $R s . 230$ per $k g$ , find the gain or loss per cent.