Coffee costing Rs. $450$ per kg was mixed with Chicory costing Rs. $225$ per kg in the ratio $5 : 2$ for a certain blend. If the mixture was sold at Rs. $405$ per kg, find the gain or loss per cent.

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Solution

Given coffee cost $= 450$ per kg
Chicory cost $= 225$ per kg
Let coffee $= 5$ x kg & chicory $= 2$ x kg $[\frac{c o f f e e}{c h i c o r y} = \frac{5}{2}]$
Total cost $= 5 x + 450 + 2 x \times 225 = 2700 x$ .
Selling price $= 7 x \times 405 = 2835 x$
S.P $>$ C.P
$∴$ It's profit
Profit percentage $= \frac{P r o f i t}{C . P} \times 100 = \frac{2835 x - 2700 x}{2700 x} \times 100$
$= \frac{/ 135 / x}{/ 2700 / x / 20}$ $\times {/ 100}_{5}$
$= 5 %$ profit.

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Coffee costing Rs. 450 per kg was mixed with Chicory costing Rs. 225 per kg in the ratio 5:2 for a certain blend. If the mixture was sold at Rs. 405 per kg, find the gain or loss per cent.

Given coffee cost =450 per kgChicory cost =225 per kgLet coffee =5x kg & chicory =2x kg [coffeechicory=52]Total cost =5x+450+2x×225=2700x.Selling price =7x×405=2835xS.P > C.P∴ It's profitProfit percentage =ProfitC.P×100=2835x−2700x2700x×100=/135/x/2700/x/20 ×/1005=5% profit.

Coffee costing Rs. $450$ per kg was mixed with Chicory costing Rs. $225$ per kg in the ratio $5 : 2$ for a certain blend. If the mixture was sold at Rs. $405$ per kg, find the gain or loss per cent.