Compare the energies of two radiations $E_{1}$ with wavelength 800 nm and $E_{2}$ with wavelength 400 nm.

E_{1} = 2 E_{2}

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E_{1} = E_{2}

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E_{2} = 2 E_{1}

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E_{2} = - \frac{1}{2} E_{1}

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Solution

The correct option is B $E_{2} = 2 E_{1}$
$E_{1} = h c / λ_{1}, E_{2} = h c / λ_{2}$
$\frac{E_{1}}{E_{2}} = \frac{h c}{λ_{1}} \times \frac{λ_{2}}{h c}$
$\frac{E_{1}}{E_{2}} = \frac{λ_{2}}{λ_{1}} = \frac{400}{800}$
$2 E_{1} = E_{2}$
option C

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