Complexes [Co(SO4(NH3)5)]Br and [CoBr(NH3)5]SO4 can be distinguished by :
A
conductance measurement
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B
using BaCl2
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C
using AgNO3
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D
all
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Solution
The correct option is D all [Co(SO4(NH3)5)]Br→[Co(SO4(NH3)5)]++Br− - gives test of bromide and [CoBr(NH3)5]SO4→[CoBr(NH3)5]+2+SO−24 - gives test of sulphate. Both complexes give different ions in solution with different charge so they can be distinguished by all these methods.