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Question

Compound X on reduction with LiAlH4 gives a hydride Y containing 21.72% hydrogen and other products. The compound Y reacts explosively with air resulting in the formation of Boron Trioxide. What are X and Y ,respectively?

A
BCl3,B2H6
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B
PCl3,B2H6
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C
B2H6,BCl3
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D
LiAlH4,PCl3
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Solution

The correct option is A BCl3,B2H6
The reaction scheme is
From the reaction scheme and the properties, it is clear that the compound Y is boron hydride. The boron hydride that contains 21.72% hydrogen is B2H6. So, Y is B2H6 (diborane). B2H6 is obtained by the reduction of BCl3 by LiAlH4. So, X is BCl3.
Reactions : 4BCl3+3LIAlH43LiCl+2B2H6+3AlCl3
B2H6+3OB2O3+3H2O

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