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Question

Compute [(3i2j2k)×(ik)]×[(i+j+k)×(i2j+3k)]

A
i16j+9k
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B
i+7j5
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C
i7j+5k
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D
i+16j9k
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Solution

The correct option is D i+16j9k
[(3i2j2k)×(ik)]×[(i+j+k)×(i2j+3k)]=[i(20)j((3)(2))+k(0(2))]×[i(3(2))j(31)+k((2)1)]=[2i+j+2k]×[5i2j3k]=i((3)(4))j((6)10)+k((4)5)=i+16j9k

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