Question

Consider a direct mapped cache of size $32KB$ with block size $32$ bytes. The $CPU$ generates $32$ bit addresses. The number of bits needed for cache indexing and the number of tag bits are respectively

• A. $10,17$
• B. $10,22$
• C. $15,17$
• D. $5,17$

Answer 1

The correct option is A $10,17$

$Sizeofcache=32KB$
$=32\times 2^{10}byte=2^5\times 2^{10}byte$
$=2^{15}byte=15bits$

$Sizeoftag=32-15=17bits$
$Cacheindex=LO-WO=15-5=10bits$