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Conversion of solid from one shape to another

Consider a fr...

Question

Consider a frustum of cone with larger and smaller radius equal to $r_{1} a n d r_{2}$ , respectively. Then, volume of frustum of a cone is $\frac{1}{3} π h (r_{1}^{2} + r_{2}^{2} + r_{1} r_{2})$ .
State whether the statement is True or False.

True

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False

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Insufficient Data

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None of the above

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Solution

The correct option is A True
Volume of frustum of a cone is
$\frac{1}{3} π h (r_{1}^{2} + r_{2}^{2} + r_{1} r_{2})$

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