Consider an electric field $\to E = E_{0}^x$ , where $E_{0}$ is a constant. The flux through the shaded area (as shown in the figure) due to this field is

\sqrt{2} E_{0} a^{2}

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2 E_{0} a^{2}

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E_{0} a^{2}

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\frac{E_{0} a^{2}}{\sqrt{2}}

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Solution

The correct option is C $E_{0} a^{2}$
$\to A = \frac{1}{2} \times_{1} \times_{2}$

$= \frac{1}{2} (a^i + a^j + a^k) \times (a^i + a^j + a^k)$

$ϕ = \to E \cdot \to A {\to E i s c o n s t a n t}$

= $E_{0} a^{2}$

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Consider an electric field →E=E0^x , where E0 is a constant. The flux through the shaded area (as shown in the figure) due to this field is

The correct option is C E0a2→A=12×→d1×→d2 =12(a^i+a^j+a^k)×(a^i+a^j+a^k) ϕ=→E⋅→A{→E is constant} =E0a2

Consider an electric field $\to E = E_{0}^x$ , where $E_{0}$ is a constant. The flux through the shaded area (as shown in the figure) due to this field is

The correct option is C $E_{0} a^{2}$
$\to A = \frac{1}{2} \times_{1} \times_{2}$

$= \frac{1}{2} (a^i + a^j + a^k) \times (a^i + a^j + a^k)$

$ϕ = \to E \cdot \to A {\to E i s c o n s t a n t}$

= $E_{0} a^{2}$