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Question

# Consider following complexes :I: [Fe(H2O)6]2+II :[Fe(CN)6]4âˆ’III :[Ni(CO)4]IV :[Ni(H2O)4]2+V :[Ni(CN)4]2âˆ’Out of this, select the complex with maximum number of magnetic moment :

A
[Fe(H2O)6]2+
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B
[Fe(CN)6]4
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C
[Ni(H2O)4]2+
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D
[Ni(CN)4]2
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Solution

## The correct option is B [Fe(H2O)6]2+[Fe(H2O)6]2+Fe is in +2 state in the above compound as H2O doesn't have any charge on it.Electronic configuration of Fe2+ is, [Ar]3d6There are four unpaired electrons in 3d orbital as H2O is a weak ligand.Magnetic Moment = √n(n+2)- √24 BM [Fe(CN)6]4−x-6= -4x= +2Fe is in +2 state in the above compound.Fe2+=[Ar]3d6There is no unpaired electron because CN− is a strong field ligand and paired the electrons due to high energy difference between t2g level and eg levelMagnetic Moment = 0[Ni(H2O)4]2+Ni is in +2 state in the above compound as H2O is neutral.Ni2+=[Ar]3d8There are two unpaired electrons in eg level. Magnetic Moment- √n(n+2)- √8 BM [Ni(CN)4]2−x-4= -2x= +2Ni is in +2 state in the above compoundNi2+=[Ar]3d8There is two unpaired electrons in eg level.Magnetic Moment- √n(n+2)- √8 BM So, the correct answer is (A)

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