Question

Consider the compounds $BC{l}_3$ and $CC{l}_4$. How will they behave with water? Justify.

Answer 1

In $BC{l}_3$, B atom is electron deficient and accepts an electron pair from water. It is hydrolyzed to boric acid.
$BC{l}_3+3H_{2}O\to H_{3}B{O}_3+3HCl$
On the other hand, $CC{l}_4$ is an electron precise molecule. C has completed its octet and cannot expand its valency shell due to absence of d orbitals. Hence, it can neither donate nor accept electrons. Hence, $CC{l}_4$ is not hydrolyzed.