Question

Consider the following frequency distribution :

Class	$0-5$	$6-11$	$12-17$	$18-23$	$24-29$
Frequency	$13$	$10$	$15$	$8$	$11$

The upper limit of the median class is

• A. $17$
• B. $17.5$
• C. $18$
• D. $18.5$

Answer 1

The correct option is B $17.5$

class	frequency	continuous class
0-5	13	0-5.5
6-11	10	5.5-11.5
12-17	15	11.5-17.5
18-23	8	17.5-23.5
24-29	11	23.5-29.5

Median class is the class where the ${\left(\frac{n+1}{2}\right)}^{th}$ term is lying.

In the given table, $n=29$

Therefore, ${\left(\frac{n+1}{2}\right)}^{th}$ value is ${\left(\frac{30}{2}\right)}^{th}=15$ which lies in the class interval $12.5-17.5$

The upper limit of median class is $17.5$