Question

Consider the following $H_2$$O_2$ solutions and choose the correct arrangement in the increasing order of normality.

A) 100 ml of 10 volumes $H_2$$O_2$ solution

B) 100 ml of 6% (w/v) $H_2$$O_2$ solution

C) 100 ml of solution containing 3.4 g of pure $H_2$$O_2$

• A. A <B <C
• B. B <A < C
• C. C < A < B
• D. A < C < B

Answer 1

The correct option is D

A < C < B

A. 10 volumes = 1.8N B. 6% $H_2$$O_2$= 3.6N C.3.4% $H_2$$O_2$ = 2N(approx.)