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Potassium Dichromate

Consider the ...

Question

Consider the following list of reagents, acidified $K_{2} C r_{2} O_{7}$ , alkaline $K M n O_{4}, C u S O_{4}, H_{2} O_{2}, C l_{2}, O_{3}, F e C l_{3}, H N O_{3}$ and $N a_{2} S_{2} O_{3}$ . The total number of reagents that can oxidise aqueous iodide to iodine is:___

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Solution

Acidified $K_{2} C r_{2} O_{7}, C u S O_{4}, H_{2} O_{2}, C l_{2}, O_{3}, F e C l_{3}$ and $H N O_{3}$ oxidise aq. iodide to iodine. Alkaline $K M n O_{4}$ oxidise aq. iodide to $I O_{3}^{-}$ .
$N a_{2} S_{2} O_{3}$ is a strong reducing agent which on reaction with $I_{2}$ produces $I^{-}$ .
$N a_{2} S_{2} O_{3} + I_{2} \to 2 I^{-} + N a_{2} S_{4} O_{6}$
Therefore, no reaction takes place between $N a_{2} S_{2} O_{3}$ and iodide ion.
Hence, correct integer is (7).

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K_{2} C r_{2} O_{7}

K M n O_{4}

C u S O_{4}

H_{2} O_{2}

C l_{2}

O_{3}

F e C l_{3}

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K_{2} C r_{2} O_{7}

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Acidified K_{2} C r_{2} O_{7}, Alkanline K M n O_{4}, C u S O_{4}, H_{2} O_{2}, C l_{2}, O_{3}, F e C l_{3}, H N O_{3}, a n d N a_{2} S_{2} O_{3}

Acidified K_{2} C r_{2} O_{7}, Alkanline K M n O_{4}, C u S O_{4}, H_{2} O_{2}, C l_{2}, O_{3}, F e C l_{3}, H N O_{3}, a n d N a_{2} S_{2} O_{3}

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{N a}_{2} S_{2} O_{3}

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