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Question

Consider the following reactions:
(i) Cu+HNO3(dil.)
(ii) Cu+HNO3(conc.)
(iii) Zn+HNO3(20%)
(iv) Zn+HNO3(60%)
Total number of reactions in which N2 is released is/are:

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Solution

The corresponding reactions are:
3Cu+8HNO3dilute2NO+3Cu(NO3)2+4H2O
Cu+4HNO3Conc.2NO2+Cu(NO3)2+2H2O
4Zn+10HNO3 (20%)4Zn(NO3)2+N2O+5H2O
Zn+4HNO3 (60%)Zn(NO3)2+2NO2+2H2O
So, total number of reactions in which N2 is released is 0.

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